Hi Andreas, Thanks for the speedy reply. The link which sent you is definitely useful. But the very basic question I wanted to get a clarification was that, what is the drive behind selection of burst time to be 577us.

Bit rate duration is determined from physical channel throughput for particular modulation schema. GMSK modulation is used with constant BT = 0.3, where B is the 3dB bandwidth of the theoretical Gaussian filter and T is duration of input data bit. Knowing B, we calculate 1/T = 1625/6 ksymb/s or approximately 270.833 ksymb/s. From here bit duration is 3.69.. μ s. Voice signal is processed in time intervals of 20ms = s/50. For that period of time throughput is [(1625/6) x (1000/50)] symbols. Because this number is fractional, let look at 6 times longer time interval. For time interval 120ms throughput is [1625 x 20] symbols or [13 x 125 x 20] symbols or [26 x 1250] symbols or [26 x 8 x 156.25] symbols. From last result we can identify: Number of symbols in a burst = 156.25 symbols, and burst time 156.25 x 3.69... = 576,92μs Number of symbols in TDMA frame is 8 x 156.25 = 1250 symbols, Number of symbols in Multiframe is 26 x 1250 symbols. On Fri, Jan 7, 2011 at 8:51 AM, Nataraju A B <natarajuab.tech(a)gmail.com> wrote: I wanted to get a clarification was that, what is the drive behind selection of burst time to be 577us. frequency should be 8Khz. If each sample is of 8 bit accuracy. This lead to 64K bits of data. ...... If we explore further on these lines we should be able to correlate to the time 577us for each burst. selection of this burst time. Otherwise what are the other end requirements led to selection of this burst time and in turn TDMA frame hierarchy. Andreas.Eversberg(a)versatel.de> wrote: