3 Mar
2014
3 Mar
'14
11:01 a.m.
Dear Holger
On 02.03.2014 08:06, Holger Hans Peter Freyther wrote:
No, the expressions can never be 0 due to
if (nchars < 0 || nchars + buf_offs >= sizeof(buf)) return "ERROR";
But even if it could, the string has already been \0 terminated by prior
calls to snprintf (the initial size value is always > 0).
Jacob
+ nchars = snprintf(buf + buf_offs, sizeof(buf)
- buf_offs,
+ "%s[L%d]> ",
+ osmo_hexdump(start, lxhs[i] - start),
+ i+1);
+ nchars = snprintf(buf + buf_offs, sizeof(buf) -
buf_offs,
+ "%s", osmo_hexdump(start, msg->tail - start));
+ nchars = snprintf(buf, sizeof(buf) - buf_offs,
+ "!!! L%d out of range", i+1);
So sizeof(buf) - buf_offs can only be 0 when the output is already null
terminated?
kind regards
holger