On Thu, Aug 21, 2014 at 01:04:38AM -0300, Igor Almeida wrote:
Hi!
dl = (struct l1ctl_info_dl *) msg->l1h;
+ msg->l2h = msg->l3h = dl->payload;
yes, looks fine. I had msg->l2h = msg->l3h = msg->tail but
dl->payload should probably work as well. I will leave it for
Sylvain/Andreas to comment.
thanks a lot for the patch
holger