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Andreas Eversberg andreas at eversberg.euDaniel Willmann wrote: >> > gettimeofday(&now_tv, NULL); >> > elapsed = ((now_tv.tv_sec - loss_tv->tv_sec) << 7) >> > + ((now_tv.tv_usec - loss_tv->tv_usec) << 7) / 1000000; >> > I assume here you're calculating the duration of the measurement period > so far and since you want to have sub-second accuracy you multiply > everything with 128. Why 128? > Is it becasue it simplifies the throughput calculation? > (tbf->meas.dl_bw_octets/elapsed in gprs_rlcmac_dl_bw()) > hi daniel, yes. first i wanted something more accurate than one second, so i multiplied the elapsed time with 128. 128 bytes are 1024 bits, so it simplifies the calculation for kbits/s. > >> > if (elapsed < 128) >> > return 0; >> > Is the intention here that the duration of the measurements is supposed > to be one second? So every second these measurements are printed out and > reset? > after every transmitted downlink frame the gprs_rlcmac_dl_bw() function is called. if at least one second is elapsed, the throughput of the time that has been elapsed is printed out. it is just a simple solution without the requirement for a timer for each TBF. regards, andreas